Halogenation, Nitration, and Sulfonation
These are three important types of electrophilic aromatic substitution (EAS) reactions, where an electrophile replaces a hydrogen atom on an aromatic ring (e.g., benzene). Below is a detailed explanation of each reaction, including their mechanisms, reagents, and examples.
1. Halogenation
- Definition:
- Halogenation is the introduction of a halogen atom (e.g., (Cl), (Br)) onto an aromatic ring.
- Electrophile: Halogen cation ((X^+)).
- Reagents:
- Halogen ((X_2), e.g., (Cl_2), (Br_2)).
- Lewis acid catalyst (e.g., (FeCl_3), (FeBr_3)).
- Mechanism:
- Formation of the Electrophile:
[
X_2 + FeX_3 \rightarrow X^+ + FeX_4^-
]- The Lewis acid ((FeX_3)) generates the halogen cation ((X^+)).
- Attack on the Aromatic Ring:
[
C_6H_6 + X^+ \rightarrow C_6H_5X^+
]- The benzene ring donates π-electrons to the halogen cation, forming a carbocation intermediate.
- Deprotonation:
[
C_6H_5X^+ + FeX_4^- \rightarrow C_6H_5X + HX + FeX_3
]- A base ((FeX_4^-)) removes a proton, restoring aromaticity and forming the halogenated product.
- Example:
[
C_6H_6 + Br_2 \xrightarrow{FeBr_3} C_6H_5Br + HBr
] - Benzene reacts with bromine to form bromobenzene.
2. Nitration
- Definition:
- Nitration is the introduction of a nitro group ((-NO_2)) onto an aromatic ring.
- Electrophile: Nitronium ion ((NO_2^+)).
- Reagents:
- Nitric acid ((HNO_3)).
- Sulfuric acid ((H_2SO_4)).
- Mechanism:
- Formation of the Electrophile:
[
HNO_3 + H_2SO_4 \rightarrow NO_2^+ + HSO_4^- + H_2O
]- Nitric acid and sulfuric acid generate the nitronium ion ((NO_2^+)).
- Attack on the Aromatic Ring:
[
C_6H_6 + NO_2^+ \rightarrow C_6H_5NO_2^+
]- The benzene ring donates π-electrons to the nitronium ion, forming a carbocation intermediate.
- Deprotonation:
[
C_6H_5NO_2^+ + HSO_4^- \rightarrow C_6H_5NO_2 + H_2SO_4
]- A base ((HSO_4^-)) removes a proton, restoring aromaticity and forming nitrobenzene.
- Example:
[
C_6H_6 + HNO_3 \xrightarrow{H_2SO_4} C_6H_5NO_2 + H_2O
] - Benzene reacts with nitric acid to form nitrobenzene.
3. Sulfonation
- Definition:
- Sulfonation is the introduction of a sulfonic acid group ((-SO_3H)) onto an aromatic ring.
- Electrophile: Sulfur trioxide ((SO_3)).
- Reagents:
- Sulfuric acid ((H_2SO_4)) or sulfur trioxide ((SO_3)).
- Mechanism:
- Formation of the Electrophile:
[
H_2SO_4 \rightarrow SO_3 + H_2O
]- Sulfuric acid generates sulfur trioxide ((SO_3)).
- Attack on the Aromatic Ring:
[
C_6H_6 + SO_3 \rightarrow C_6H_5SO_3^+
]- The benzene ring donates π-electrons to sulfur trioxide, forming a carbocation intermediate.
- Deprotonation:
[
C_6H_5SO_3^+ + HSO_4^- \rightarrow C_6H_5SO_3H + H_2SO_4
]- A base ((HSO_4^-)) removes a proton, restoring aromaticity and forming benzenesulfonic acid.
- Example:
[
C_6H_6 + SO_3 \xrightarrow{H_2SO_4} C_6H_5SO_3H
] - Benzene reacts with sulfur trioxide to form benzenesulfonic acid.
Summary of Halogenation, Nitration, and Sulfonation:
Reaction | Electrophile | Reagents | Product |
---|---|---|---|
Halogenation | (X^+) | (X_2 + FeX_3) | Halobenzene ((C_6H_5X)). |
Nitration | (NO_2^+) | (HNO_3 + H_2SO_4) | Nitrobenzene ((C_6H_5NO_2)). |
Sulfonation | (SO_3) | (H_2SO_4) or (SO_3) | Benzenesulfonic acid ((C_6H_5SO_3H)). |
Practice Problems:
- Halogenation:
- Predict the product of the reaction: [ C_6H_6 + Cl_2 \xrightarrow{FeCl_3} ? ]
- Answer: Chlorobenzene ((C_6H_5Cl)).
- Nitration:
- Predict the product of the reaction: [ C_6H_6 + HNO_3 \xrightarrow{H_2SO_4} ? ]
- Answer: Nitrobenzene ((C_6H_5NO_2)).
- Sulfonation:
- Predict the product of the reaction: [ C_6H_6 + SO_3 \xrightarrow{H_2SO_4} ? ]
- Answer: Benzenesulfonic acid ((C_6H_5SO_3H)).
These reactions are fundamental in organic chemistry for introducing functional groups onto aromatic rings, enabling the synthesis of a wide range of compounds.