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Halogenation, Nitration, and Sulfonation

These are three important types of electrophilic aromatic substitution (EAS) reactions, where an electrophile replaces a hydrogen atom on an aromatic ring (e.g., benzene). Below is a detailed explanation of each reaction, including their mechanisms, reagents, and examples.


1. Halogenation

  • Definition:
  • Halogenation is the introduction of a halogen atom (e.g., (Cl), (Br)) onto an aromatic ring.
  • Electrophile: Halogen cation ((X^+)).
  • Reagents:
  • Halogen ((X_2), e.g., (Cl_2), (Br_2)).
  • Lewis acid catalyst (e.g., (FeCl_3), (FeBr_3)).
  • Mechanism:
  1. Formation of the Electrophile:
    [
    X_2 + FeX_3 \rightarrow X^+ + FeX_4^-
    ]
    • The Lewis acid ((FeX_3)) generates the halogen cation ((X^+)).
  2. Attack on the Aromatic Ring:
    [
    C_6H_6 + X^+ \rightarrow C_6H_5X^+
    ]
    • The benzene ring donates π-electrons to the halogen cation, forming a carbocation intermediate.
  3. Deprotonation:
    [
    C_6H_5X^+ + FeX_4^- \rightarrow C_6H_5X + HX + FeX_3
    ]
    • A base ((FeX_4^-)) removes a proton, restoring aromaticity and forming the halogenated product.
  • Example:
    [
    C_6H_6 + Br_2 \xrightarrow{FeBr_3} C_6H_5Br + HBr
    ]
  • Benzene reacts with bromine to form bromobenzene.

2. Nitration

  • Definition:
  • Nitration is the introduction of a nitro group ((-NO_2)) onto an aromatic ring.
  • Electrophile: Nitronium ion ((NO_2^+)).
  • Reagents:
  • Nitric acid ((HNO_3)).
  • Sulfuric acid ((H_2SO_4)).
  • Mechanism:
  1. Formation of the Electrophile:
    [
    HNO_3 + H_2SO_4 \rightarrow NO_2^+ + HSO_4^- + H_2O
    ]
    • Nitric acid and sulfuric acid generate the nitronium ion ((NO_2^+)).
  2. Attack on the Aromatic Ring:
    [
    C_6H_6 + NO_2^+ \rightarrow C_6H_5NO_2^+
    ]
    • The benzene ring donates π-electrons to the nitronium ion, forming a carbocation intermediate.
  3. Deprotonation:
    [
    C_6H_5NO_2^+ + HSO_4^- \rightarrow C_6H_5NO_2 + H_2SO_4
    ]
    • A base ((HSO_4^-)) removes a proton, restoring aromaticity and forming nitrobenzene.
  • Example:
    [
    C_6H_6 + HNO_3 \xrightarrow{H_2SO_4} C_6H_5NO_2 + H_2O
    ]
  • Benzene reacts with nitric acid to form nitrobenzene.

3. Sulfonation

  • Definition:
  • Sulfonation is the introduction of a sulfonic acid group ((-SO_3H)) onto an aromatic ring.
  • Electrophile: Sulfur trioxide ((SO_3)).
  • Reagents:
  • Sulfuric acid ((H_2SO_4)) or sulfur trioxide ((SO_3)).
  • Mechanism:
  1. Formation of the Electrophile:
    [
    H_2SO_4 \rightarrow SO_3 + H_2O
    ]
    • Sulfuric acid generates sulfur trioxide ((SO_3)).
  2. Attack on the Aromatic Ring:
    [
    C_6H_6 + SO_3 \rightarrow C_6H_5SO_3^+
    ]
    • The benzene ring donates π-electrons to sulfur trioxide, forming a carbocation intermediate.
  3. Deprotonation:
    [
    C_6H_5SO_3^+ + HSO_4^- \rightarrow C_6H_5SO_3H + H_2SO_4
    ]
    • A base ((HSO_4^-)) removes a proton, restoring aromaticity and forming benzenesulfonic acid.
  • Example:
    [
    C_6H_6 + SO_3 \xrightarrow{H_2SO_4} C_6H_5SO_3H
    ]
  • Benzene reacts with sulfur trioxide to form benzenesulfonic acid.

Summary of Halogenation, Nitration, and Sulfonation:

ReactionElectrophileReagentsProduct
Halogenation(X^+)(X_2 + FeX_3)Halobenzene ((C_6H_5X)).
Nitration(NO_2^+)(HNO_3 + H_2SO_4)Nitrobenzene ((C_6H_5NO_2)).
Sulfonation(SO_3)(H_2SO_4) or (SO_3)Benzenesulfonic acid ((C_6H_5SO_3H)).

Practice Problems:

  1. Halogenation:
  • Predict the product of the reaction: [ C_6H_6 + Cl_2 \xrightarrow{FeCl_3} ? ]
    • Answer: Chlorobenzene ((C_6H_5Cl)).
  1. Nitration:
  • Predict the product of the reaction: [ C_6H_6 + HNO_3 \xrightarrow{H_2SO_4} ? ]
    • Answer: Nitrobenzene ((C_6H_5NO_2)).
  1. Sulfonation:
  • Predict the product of the reaction: [ C_6H_6 + SO_3 \xrightarrow{H_2SO_4} ? ]
    • Answer: Benzenesulfonic acid ((C_6H_5SO_3H)).

These reactions are fundamental in organic chemistry for introducing functional groups onto aromatic rings, enabling the synthesis of a wide range of compounds.

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